Question

Can someone help?

Answer 1

with what

Answer 2

@mathstudent55

Answer 3

do you need help with that

Answer 4

Yes

Answer 5

@austinL

Answer 6

@aliciabennett add the two fractions first and show what you get.

Answer 7

Well first multiply both sides by 2x, and then by 3x-1. Then fiddle with it.

Answer 8

You cant can you? I thought you needed a LCD

Answer 9

You don't need do multiply by the GCD (greatest common divisor), you just need to multiply by some common divisor of the two denominators. (2x)(3x-1) satisfies this. It is also the GCD though.

Answer 10

or I'm sorry, should be LCM. my bad. anyway.

Answer 11

I am so confused :/

Answer 12

\(\dfrac{4}{3x+1}+\dfrac{1}{2x}=\dfrac{3}{2x}\)

First you can subtract the \(\dfrac{1}{2x}\) from both sides to get,

\(\dfrac{4}{3x+1}=\dfrac{2}{2x}\)

Answer 13

Then you can cross multiply and then solve.

Answer 14

Hello?

Answer 15

6x+2/8x

Answer 16

\(\dfrac{4}{3x+1}=\dfrac{2}{2x}\)

Cross multiply.
\(2(3x+1)=4(2x)\Rightarrow~6x+2=8x\)

Answer 17

Have you arrived at an answer @aliciabennett ?

Answer 18

Not at all @austinL