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Find a counterexample for the conjecture three coplanar lines always make a triangle.
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If 3 lines are collinear, then they do not span more than a line: |dw:1380059753903:dw|
If you have an system, \(S\) of the following: \[S=\left\{\eqalign{ &y=ax+c_1 \\ &y=ax+c_2 \\ &y=ax+c_3 \\ }\right.\] They will never intersect. In other words, if they had the same slope, they would never form a triangle
Even if just two are parallel, then no triangle can be formed.
As well If you had a system where the three lines intersected eachother ONLY ONCE. Such as in the case of: \[S=\left\{\eqalign{ &y=m_1(x-h)+k \\ &y=m_2(x-h)+k \\ &y=m_3(x-h)+k \\ }\right.\] Which has the solution \((h,k)\)
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