MEDAL

Find the point at which the line y = 6x − 17 is tangent to the graph of y = e^(x^2−9)

the point of tangency is

Question

MEDAL

Find the point at which the line y = 6x − 17 is tangent to the graph of y = e^(x^2−9)

the point of tangency is

blockcolder · Answer

Find the point(s) on y=e^(x^2-9) where the slope is 6.
If there is more than one, check whether they satisfy y=6x-17.

anonymous · Answer

is it x=3?

anonymous · Answer

@Luigi0210 need help

psymon · Answer

Yeah, find the derivative and then set the derivative equal to 6. A derivative just gives you the formula for slope. If you want as specific slope, set the derivative equal to that slope. So see if you can find an x value in the derivative that will get you an answer of 6 and then you can go from there.

anonymous · Answer

I got the x value what is y?

psymon · Answer

So it looks liek 3 is the only point where youd have a slope of 6. SO now plug 3 back into the original equation to get your y-coordinate.

anonymous · Answer

orginal equation is e^(x^2-9) or 6x-17?

psymon · Answer

e^(x^2-9)

anonymous · Answer

so y is 1 thanks

psymon · Answer

Right. So now all you would need to do is use the slope of 6 and the point (3,1) and make sure it gave you the correct tangent line graph by using point-slope form.