suppose that the tangent line to y=g(x) at (-3, 5) passes through the point (2,-4). find g(-3), g'(-3), and the equation of the tangent line to y=g(x) at (-3,5)

Question

agent0smith · Answer

Use the slope formula   (y2-y1)/(x2-x1) to find g'(-3)... since it's the slope. Your points are  (-3, 5) and (2,-4).

You already know g(-3) = 5 since "y=g(x) at (-3, 5)"

agent0smith · Answer

Tangent line is y=mx+b, m is the slope you just found, g'(-3), and plug in the point that it passes through (-3, 5) to find b.

anonymous · Answer

so G'(-3) just means the slope?

agent0smith · Answer

Yep. Since the slope of the tangent line is the slope of g(-3)

anonymous · Answer

hmm okay, thank you!

agent0smith · Answer

|dw:1380068669647:dw|
remember that slope of the tangent line IS the slope of the function, at that point