Mathematics
8 Online
OpenStudy (anonymous):
Hi
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
well y = -(x+1)^2+9 is practically in vertex form already
do you see how?
OpenStudy (anonymous):
no
jimthompson5910 (jim_thompson5910):
y = -(x+1)^2+9
is the same as
y = -1(x- (-1))^2+9
see it now?
OpenStudy (anonymous):
yeah
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
whats next
jimthompson5910 (jim_thompson5910):
compare it to y=a(x-h)^2+k
jimthompson5910 (jim_thompson5910):
tell me what a, h, k are equal to
OpenStudy (anonymous):
a=-1 h=1 k=9
OpenStudy (anonymous):
@jim_thompson5910 what do I do next
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@charlotte123
OpenStudy (charlotte123):
@MayMay_69 didn't study this yet D: try wolframalpha ^-^
OpenStudy (anonymous):
I can't find him can you tag him for me
OpenStudy (anonymous):
h=-1, a=-1, k=9
OpenStudy (charlotte123):
@wio your pic is so cute ^O^
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
It already is in vertex form.
OpenStudy (anonymous):
Thanks @charlotte123
OpenStudy (anonymous):
really?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
okay what about this one, y=(-x+10) (x+2)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
First expand it out. Can you do that?
OpenStudy (anonymous):
No sorry
OpenStudy (anonymous):
could u help me please
OpenStudy (anonymous):
@Mertsj
OpenStudy (mertsj):
The requirement is that you write each problem in vertex form.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
Then the problem tells you that vertex form is y = a(x-h)^2+k
OpenStudy (mertsj):
So your job is to make each equation look exactly like that.
OpenStudy (mertsj):
|dw:1380076124263:dw|