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Mathematics 8 Online
OpenStudy (anonymous):

Hi

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

well y = -(x+1)^2+9 is practically in vertex form already do you see how?

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

y = -(x+1)^2+9 is the same as y = -1(x- (-1))^2+9 see it now?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

whats next

jimthompson5910 (jim_thompson5910):

compare it to y=a(x-h)^2+k

jimthompson5910 (jim_thompson5910):

tell me what a, h, k are equal to

OpenStudy (anonymous):

a=-1 h=1 k=9

OpenStudy (anonymous):

@jim_thompson5910 what do I do next

OpenStudy (anonymous):

@charlotte123

OpenStudy (charlotte123):

@MayMay_69 didn't study this yet D: try wolframalpha ^-^

OpenStudy (anonymous):

I can't find him can you tag him for me

OpenStudy (anonymous):

h=-1, a=-1, k=9

OpenStudy (charlotte123):

@wio your pic is so cute ^O^

OpenStudy (anonymous):

It already is in vertex form.

OpenStudy (anonymous):

Thanks @charlotte123

OpenStudy (anonymous):

really?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

okay what about this one, y=(-x+10) (x+2)

OpenStudy (anonymous):

First expand it out. Can you do that?

OpenStudy (anonymous):

No sorry

OpenStudy (anonymous):

could u help me please

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

The requirement is that you write each problem in vertex form.

OpenStudy (mertsj):

Then the problem tells you that vertex form is y = a(x-h)^2+k

OpenStudy (mertsj):

So your job is to make each equation look exactly like that.

OpenStudy (mertsj):

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