Balance this equation: 1. P4 + O2 ----> P2 + O5 2. C2H6 + O2 ----> CO2 + H2O
When balancing chemical equations, add only coefficients (never change the subscripts). Therefore, count the number of each ion on each side and see if you can add a number in front to make the ion count the same.
\[P _{4}+O _{2}--->P _{2}+O _{5}\]
Eg. For the first equation, you have 2 P ions on the right side and 4 P ions on the left. To make them the same, add a coefficient of 2 in front of the P2. Then count the O ions on each side. You have 5 on one side, and 2 on the other, therefore add a coefficient of 5 to O2 and a coefficient of 2 to O5 so that there'll be 10 oxygens on each side of the arrow. Give the other one a try.
I'm thinking..... put a 3 behind H2 O, and then a 2 in front of CO2. Does this sound right?
If you do that, you'd have balanced the C and H ions, but not the oxygens. You now have 7 oxygens on one side, and only 2 on the other. You may have to play around with the coefficients of the other compounds to balance out the O.
How do you do fractional coefficients work? I need 02 to get to that O7?
Coefficients can only be whole numbers, so look back at the equation and see if you can do anything to the 3H2O (since the 3 is what causes the odd number of oxygen ions). If you try doubling it, you would get 6H2O and in that case, you can add a 7 in front of the O2 to make it balanced. Now the other compounds are unbalanced, so try changing the coefficients for them. Balancing equations is really just a lot of guesswork, but you get better at them the more you practice.
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