Question

show that if an \(n*n\) matrix has eigenvalues \(\lambda_1, \lambda_2,...,\lambda_n\) (not necessarily distinct) with linearly independent eigenvectors\[x_1,x_2,...,x_n\]respectively, then a general solution of \(x'=Ax\) is \(x(t)=c_{1}e^{\lambda_{1}t}x_{1}+...+c_{n}e^{\lambda_{n}t}x_{n}\)

Answer 1

@Directrix help please?