Question

HELP PLEASE! SHOW ME HOW TO DO IT AND NOT JUST GIVE ME THE ANSWER.


27x4 – 90x2 + 75

Answer 1

might the question be "factor \(27x^4 – 90x^2 + 75\)"?

Answer 2

yes

Answer 3

factor out a 3 from the whole thing first

Answer 4

then we can proceed, assuming you don't want just the answer

Answer 5

9 - 30+25

Answer 6

don't forget the variables and the 3 out front!
\[3(9x^4-30x^2+25)\]

Answer 7

I didnt, i was just giving you the numbers

Answer 8

so is that the answer?

Answer 9

ok now you are supposed to recognize the second part as a perfect square
\[(a-b)^2=a^2-2ab+b^2\] and in this case \(a=3x^2,b=5\)

Answer 10

so no, that is not the final answer, that is the first step

Answer 11

final answer is what you get when you make the above replacements, namely
\[3(3x^2-5)^2\]

Answer 12

@satellite73 can you help me with 2 more please?

Answer 13

sure

Answer 14

32x6 – 162

Answer 15

\[32x^6-162\] common factor of \(2\) gives
\[2(16x^6-81)\]

Answer 16

this time you are supposed to recognize \(16x^6-81\) as the difference of two squares
\[a^2-b^2=(a+b)(a-b)\] with \(a=4x^3, b=9\)

Answer 17

final answer here is therefore
\[2(4x^3+9)(4x^3-9)\]

Answer 18

clear enough?

Answer 19

yes. TY. one more lol

Answer 20

5x3 – 35x2 + 60x

Answer 21

this time factor out the common factor of \(5x\)

Answer 22

start with
\[5x(x^2-7x+12)\]

Answer 23

then the question is how to factor \(x^2-7x+12\)
do you know how or would you like me to show you?

Answer 24

(x )(x ) find the factors of 12 that add up to -7?

Answer 25

yes

Answer 26

obviously they are both negative, since \(-7\) is negative and \(+12\) is positive

Answer 27

(x-4)(x-3)

Answer 28

you got it
final answer is
\[5x(x-4)(x-3)\]