Question

n!(n+1)

Answer 1

make a guess

Answer 2

2n!
?

Answer 3

or maybe it would be easier to see if you wrote it as \[(n+1)n!\]

Answer 4

oh no

Answer 5

n^3!
?

Answer 6

for example, if \(n=5\) you would have
\[6\times 5!=6\times 5\times 4\times 3\times 2\times 1\]

Answer 7

OH .. so it would still be n!

Answer 8

no in this case \(n\) was \(5\) and so \(n+1=6\)

Answer 9

i.e. it would be \((n+1)!\)

Answer 10

What are the steps to getting there though?