Question

Find the vertex and find the axis of symmetry for each..

1. -3x^2 +1 2. y=-4x^ -2x+9

Answer 1

@Zale101

Answer 2

@Luigi0210

Answer 3

plase help.....

Answer 4

I don't know this

Answer 5

Take the derivative

Answer 6

the wat?

Answer 7

@aaronq

Answer 8

@ganeshie8

Answer 9

easy way is to convert given equation to vertex form :-

\(\large a(x-h)^2 + k \)

\((h, k )\) is the vertex

\(x = h\) is the axis of symmetry

Answer 10

take first equation :-
1. \(-3x^2 + 1\)

is same as,

\(-3(x-0)^2 + 1 \)

Answer 11

simply, compare it wid vertex form, and write down vertex

Answer 12

wait so the vertext is (0,1)?

Answer 13

Yup ! good job !!

Answer 14

once u have vertex,
axis of symmetry is simply its x-coordinate

Answer 15

here, axis of symmetry is the line

\(x = 0 \)

Answer 16

Taking a derivative is what you learn in calculus. When the derivative equals zero it is a way to find maximums and minimums .
1. -3x^2 +1
2. y=-4x^ -2x+9

Equation 1
-3x^2 +1
The derivative -6x equals zero when x = 0
When x = 0, the 'y' value is
y = -3*0 +1
y = 1
So the vertex is at (0, 1)
Since the x² coefficient is negative, the graph is concave down and the vertex is a maximum.