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Mathematics 20 Online
OpenStudy (anonymous):

limits question: f(x)=9x^2−4x+9. Then: lim h⟶0 f(x+h)−f(x) / h =____ I'm guessing I have to factor out the first function and once I get a value for x, I sub it in for the lim. I'm having difficulties factoring it out though.

hartnn (hartnn):

what u got as f(x+h) ?

OpenStudy (anonymous):

what do you mean?

OpenStudy (anonymous):

I thought i'd have to factor out the function first...the quadratic function and solve for x?

hartnn (hartnn):

to find f(x+h) we need to plug in 'x+h' instead of every x, in f(x)

OpenStudy (anonymous):

i've been stuck on this for the last hour...

OpenStudy (anonymous):

I thought i'd have to factor out the function first...the quadratic function and solve for x?

hartnn (hartnn):

not required , first find f(x+h)

OpenStudy (anonymous):

\[9x^2+9h^2+18xh-4x-4h+9\]

OpenStudy (anonymous):

is that what you mean? sorry I got disconnected from this site.

hartnn (hartnn):

correct! now the numerator is f(x+h)-f(x) find this, and see what cancels out

OpenStudy (anonymous):

but after i do that i get: 9h+18x-4

hartnn (hartnn):

absolutely correct! the 'h's got cancelled, right ? :) now you can just plug in h=0 in that expression :)

OpenStudy (anonymous):

yes! thank-you, genius!

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

oh no, i ended up with 9h+18x-4 and solved for x = 2/9, but when i went to go submit that it turned out incorrect

hartnn (hartnn):

when u put h=0 you just get 18x-4 thats your answer no need to solve

OpenStudy (anonymous):

ahhhh, that came out as correct! why don't we need to solve it though?

hartnn (hartnn):

nopes. you already solved that limit by plugging h=0

OpenStudy (anonymous):

oh i see, thanks a lot! xo.

hartnn (hartnn):

welcome ^_^

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