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Using the oxidation number method, balance the following ionic equation for basic solution. http://prntscr.com/1tcf8g
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\[I^-+Ce ^{4+}\rightarrow IO _{3}^-+6Ce^{3+}\]
I believe the ratio is 6:1, therefore I came up with a coefficient of 6 for both Ce^4+ and Ce^3+, but I'm not sure where to go from there.
You're right. The following step requires the condition that the reaction is in basic solution. So, you'll have something like, \[Ce^{+4}+1e^-\rightarrow Ce^{3+}\]\[6OH+I^-\rightarrow IO_3^-+3H_2O+6e^-\]
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