.
\(\huge \frac{1}{\sqrt[3]{x^{-6}}}\)
@Nurialozza96
here(:
first exponent property we will be using :- \(\huge \color{Red}{\sqrt[n]{a^{m}} = a^{\frac{m}{n}}} \)
lets apply it for the bottom expression and see wat we get
ok let me do it on paper and see
\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \)
and from there?
\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \)
\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \) \(\huge \frac{1}{x^{-2}} \)
you're okay wid those four lines right ? :)
3 goes in 6, 2 times... thats all i did
yes, the problem is they ask me to justify each step
we have justified second step using the exponent property
ok in the first step is those 4 correct?
\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) cuz, \(\huge \color{Red}{\sqrt[n]{a^{m}} = a^{\frac{m}{n}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \) \(\huge \frac{1}{x^{-2}} \)
there, the justfication goes
so that would be the final answer? this last one you posted?
second exponent property we use is below :- \(\huge \color{Red}{\frac{1}{a^{-m}} = a^{m} }\)
\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) cuz, \(\huge \color{Red}{\sqrt[n]{a^{m}} = a^{\frac{m}{n}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \) \(\huge \frac{1}{x^{-2} }\) \(\huge x^2 \) cuz, \(\huge \color{Red}{\frac{1}{a^{-m}}} = a^{m} \)
we're done final answer after simplification is x^2
so that would be the final answer? im going to study and copare it to my others ones to make sure i got them right .
what does "^" mean ?
^ means, exponent
ohhh ok ok thankyou ! (:
np :)
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