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Mathematics 18 Online
ganeshie8 (ganeshie8):

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ganeshie8 (ganeshie8):

\(\huge \frac{1}{\sqrt[3]{x^{-6}}}\)

ganeshie8 (ganeshie8):

@Nurialozza96

OpenStudy (anonymous):

here(:

ganeshie8 (ganeshie8):

first exponent property we will be using :- \(\huge \color{Red}{\sqrt[n]{a^{m}} = a^{\frac{m}{n}}} \)

ganeshie8 (ganeshie8):

lets apply it for the bottom expression and see wat we get

OpenStudy (anonymous):

ok let me do it on paper and see

ganeshie8 (ganeshie8):

\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \)

OpenStudy (anonymous):

and from there?

ganeshie8 (ganeshie8):

\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \)

ganeshie8 (ganeshie8):

\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \) \(\huge \frac{1}{x^{-2}} \)

ganeshie8 (ganeshie8):

you're okay wid those four lines right ? :)

ganeshie8 (ganeshie8):

3 goes in 6, 2 times... thats all i did

OpenStudy (anonymous):

yes, the problem is they ask me to justify each step

ganeshie8 (ganeshie8):

we have justified second step using the exponent property

OpenStudy (anonymous):

ok in the first step is those 4 correct?

ganeshie8 (ganeshie8):

\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) cuz, \(\huge \color{Red}{\sqrt[n]{a^{m}} = a^{\frac{m}{n}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \) \(\huge \frac{1}{x^{-2}} \)

ganeshie8 (ganeshie8):

there, the justfication goes

OpenStudy (anonymous):

so that would be the final answer? this last one you posted?

ganeshie8 (ganeshie8):

second exponent property we use is below :- \(\huge \color{Red}{\frac{1}{a^{-m}} = a^{m} }\)

ganeshie8 (ganeshie8):

\(\huge \frac{1}{\sqrt[3]{x^{-6}}} \) \(\huge \frac{1}{x^{\frac{-6}{3}}} \) cuz, \(\huge \color{Red}{\sqrt[n]{a^{m}} = a^{\frac{m}{n}}} \) \(\huge \frac{1}{x^{\frac{-\cancel{6}{2}}{\cancel{3}}}} \) \(\huge \frac{1}{x^{-2} }\) \(\huge x^2 \) cuz, \(\huge \color{Red}{\frac{1}{a^{-m}}} = a^{m} \)

ganeshie8 (ganeshie8):

we're done final answer after simplification is x^2

OpenStudy (anonymous):

so that would be the final answer? im going to study and copare it to my others ones to make sure i got them right .

OpenStudy (anonymous):

what does "^" mean ?

ganeshie8 (ganeshie8):

^ means, exponent

OpenStudy (anonymous):

ohhh ok ok thankyou ! (:

ganeshie8 (ganeshie8):

np :)

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