Question

find dy/dx
y=sin(x)+(1/2)cot(x)

don't give me the answer. i want to work through with it

Answer 1

Pretty straight forward

Answer 2

What have you did?

Answer 3

[sin (x)]((1/2)cot(x))+(sin (x))[1/2)cot(x)]

Answer 4

(cos(x))(1/2)cot(x))+(sin (x))((1/2)csc^2(x))

Answer 5

what do i do after that?

Answer 6

That is wrong

Answer 7

What is the dy/dx of sin, and the dy/dx of cot

Answer 8

sin(x) is cos(x) and cot(x) is csc^2(x) right?

Answer 9

First u divided 2 part dy/dx or sin = cos(x) right, then next part u take dx/dx or 1/2cot(x)

Answer 10

-csc^2

Answer 11

So the answer is be y= cos (x) - csc^2 (x) I guess

Answer 12

u mean Y= cos (x) - (1/2)csc^2 (x)