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find the polar form of i^7+i^10
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first simplify i^7 and i^10 ?
that would be z=-1-i...rite?
yes!
know how to get polar form ?
i m just confused at d part where u hv 2 find thita
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theta = tan inverse y/x
theta = tan inverse (-1/-1)
z=r(\[\cos \theta + i\])
ooppss
z= r cos theta+ i r sin theta
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i mean z=r(cos theta+i sin theta)
r =... ?
so i get tan inverse 1 so i m gettin theta as pi/4 but d ans says its 3pi/4
r i got as root 2
yes, and i'll tell u the reason you tell me your r is positive or negative ?
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positive
-1-i = -(1+i)
so, - root 2 angle 45
yep
but r cannot be negative so, +root 2 angle (45-180)
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hold on...45-180 kyu kiya?
it cannot b negative so? -180?
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