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Chemistry 9 Online
OpenStudy (anonymous):

How do you determine the units for the rate constant?

OpenStudy (aaronq):

it depends on the order of the reaction

OpenStudy (anonymous):

What if it is a fourth order reaction

OpenStudy (aaronq):

Zero order -> \(M^1 s^{-1} = M/s \) First order --> \(M^0 s^{-1} = 1/s \) Second order ->\( M^{-1} s^{-1} = L/mol* s\) can you see the pattern?

OpenStudy (anonymous):

But why is mols there for the second order???

OpenStudy (aaronq):

because of the nature of the equation rate=\(k[X]^2\), you'll end up with /mol

OpenStudy (anonymous):

Ooooooooooh I seee! Thank you very much :) You are very helpful!

OpenStudy (aaronq):

no problem, dude! glad i could help

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