Question

how would you put y=6x-8 into standard form by USING the point (6,-2)

Answer 1

help please!

Answer 2

I don't see how or why you'd need to use the point (6, -2)...

Standard form is Ax+By=C,

A, B, C are all integers, GCF of 1, and A is positive. So, get all the x's and y's on one side, leave all the numbers on the other.

Start by subtracting 6x on both sides.

Answer 3

the original line/equation was: y=6x-8

Answer 4

and u have to make it into AX+BY=C

Answer 5

so do i have to substitute the y for the y and x for x?

Answer 6

Read my post above... it has the steps to get started. You don't need to use the point (6, -2).

Answer 7

U HAVE TO ACCORDING TO MY SHEET :P

Answer 8

u have to right the equation of the line in standard form that is perpendicular to the other line and passes through the point (6,-2)

Answer 9

Then you didn't post the whole question at the start... "equation of the line in standard form that is perpendicular to the other line and passes through the point (6,-2)" this is not the same as what you posted at the top.

First, you need to find a line that is perpendicular the y=6x-8, and passes through (-6, 2)

Answer 10

oh sorry :\

Answer 11

and how would u do that, i already drew the line for y=6x-8

Answer 12

hmm?

Answer 13

Do you know how to find the slope of a perpendicular line?

Answer 14

It's the negative reciprocal of the original line. eg if the original line has slope 2, the perp. line has slope -1/2