Question

An unknown compound contains only C, H, and O. Combustion of 3.10 g of this compound produced 7.05 g of CO2 and 2.88 g of H2O.

Answer 1

apply the exact same concept as the last question.

Answer 2

except this time you also have oxygen

Answer 3

i don't fully understand what you did last time...

Answer 4

find the moles of each

moles of carbon = moles of CO2

moles of H are = moles of H2O (x2) (because there are 2 H atoms)

moles of O are = moles of H2O + moles of CO2 (x2) .. again, because 2 atoms of O.

Answer 5

divide them all by the one with the least moles, and multiply them by a number to get them all as whole numbers.

Answer 6

so 7.05/44=0.160227273/0.159857904=1.002310607
and 2.88/18.016=0.159857904/0.159857904=1
this makes no sense..

Answer 7

hey after you helap her canone or both of you guys help me on my question i posted in chem

Answer 8

do it in steps;

moles of carbon= 7.05/44=0.160227273

moles of H 2.88/18.016 *2=

moles of O = 0.160227273*2+(2.88/18.016)=

Answer 9

2.88/18.016 *2=0.319715808
0.160227273*2+(2.88/18.016)=0.48031245
now what?

Answer 10

divide all by the species with the lowest amount of moles

Answer 11

so
0.160227273/0.160227273=1
0.319715808/0.160227273=1.995389437=2
0.48031245/0.160227273=2.997694718=3
so its \[CH _{2} O _{3}\]?

Answer 12

nope.. that's not it.. ): i actually got excited for a minute.. I suck..

Answer 13

\[CH _{9}O _{6}\]?

Answer 14

dang it! nope.. that's not it either..

Answer 15

help me.. i've tried four times and was wrong everytime..

Answer 16

that's it.. i give up..

Answer 17

\[C _{3}H _{6}O\] is the answer..

Answer 18

thanks for all your help though!