Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
@zepdrix
OpenStudy (anonymous):
your teacher loves you...
OpenStudy (anonymous):
hahaha
OpenStudy (anonymous):
let me know if you need any help
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i just don't know where to start..
OpenStudy (anonymous):
well from anything less than or equal to 1 it will always be 2/3
OpenStudy (anonymous):
the first 2 functions either line up (have the same y value) as x -> 1 or they don't.
you have to evaluate if they do or don't.
OpenStudy (anonymous):
well for the 2nd function, at 1, it doesn't exist...
OpenStudy (anonymous):
so there is a dis-continuity
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
right, but see if you can factor out the bad part. you have a difference of cubes which factors easily.
one of the factors is (x-1) the other is x^2+x+1
see if the top has a factor of (x-1). if it does, you can cancel (remember, you're only interested in the limit of that function as it approaches 1 from the right (above)).
OpenStudy (anonymous):
not necessarily a discontinuity... you have to check. follow what I said and see what comes out.
OpenStudy (anonymous):
alright. let me work on that
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
hint, x-1 is a factor of the numertor too
Still Need Help?
Join the QuestionCove community and study together with friends!