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Mathematics 14 Online
OpenStudy (anonymous):

discontinuities

OpenStudy (anonymous):

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

your teacher loves you...

OpenStudy (anonymous):

hahaha

OpenStudy (anonymous):

let me know if you need any help

OpenStudy (anonymous):

i just don't know where to start..

OpenStudy (anonymous):

well from anything less than or equal to 1 it will always be 2/3

OpenStudy (anonymous):

the first 2 functions either line up (have the same y value) as x -> 1 or they don't. you have to evaluate if they do or don't.

OpenStudy (anonymous):

well for the 2nd function, at 1, it doesn't exist...

OpenStudy (anonymous):

so there is a dis-continuity

OpenStudy (anonymous):

right, but see if you can factor out the bad part. you have a difference of cubes which factors easily. one of the factors is (x-1) the other is x^2+x+1 see if the top has a factor of (x-1). if it does, you can cancel (remember, you're only interested in the limit of that function as it approaches 1 from the right (above)).

OpenStudy (anonymous):

not necessarily a discontinuity... you have to check. follow what I said and see what comes out.

OpenStudy (anonymous):

alright. let me work on that

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

hint, x-1 is a factor of the numertor too

OpenStudy (anonymous):

yep|dw:1380152342904:dw|

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