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Chemistry 8 Online
OpenStudy (anonymous):

How many atoms of phosphorus are in 3.30 mol of copper(II) phosphate?

OpenStudy (anonymous):

\[3.3 mol(\frac{6.022x10^{23}}{1 mol})=?\]

OpenStudy (anonymous):

check my conversion factor

OpenStudy (anonymous):

so is it 1.98x10^24

OpenStudy (anonymous):

looks good to me do you understand the factor label method to set up these problems?

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