Question

What is the maximum (highest) point on the graaph of this quadratic function: f(x)=-2x^2+8x+10 ? Help Please

Answer 1

Even seen "-b/(2a)"?

Answer 2

Yea. Isn't that how to get the vertex? I think?

Answer 3

Perfect. That IS how to find the vertex. The vertex is the highest or lowest point that you seek.

Answer 4

y = -2x^2 + 8x + 10

you could also try the derivative to find the point

y'= -4x + 8

then set y' to 0

4x = 8
x=2

then substitute to the quadratic

y = -2(2^2) + 8(2) + 10
y = 18
since y" is negative we could conclude that (2, 18) is a maxima

kindly correct me if i missed or i was wrong at something

Answer 5

It's okay thanks. I'm barely starting to learn to do this but yea I get it in a way.

Answer 6

Notice also how from y = -2x^2 + 8x + 10 we have -8/(2(-2)) = -8/(-4) = 2 and we have managed to use the calculus to find the same result.