3/7 * 1/3 + 4/7 * 3/8 =Simplify your answer use order of operations
\[\large \frac{3}{7}*\frac{1}{3}+\frac{4}{7}*\frac{3}{8}\] \[\large \frac{3*1}{7*3}+\frac{4*3}{7*8}\] \[\large \frac{3}{21}+\frac{12}{56}\] \[\large \frac{1}{7}+\frac{3}{14}\] \[\large \frac{1*2}{7*2}+\frac{3}{14}\] \[\large \frac{2}{14}+\frac{3}{14}\] \[\large \frac{2+3}{14}\] \[\large \frac{5}{14}\] ======================================================= So, \[\large \frac{3}{7}*\frac{1}{3}+\frac{4}{7}*\frac{3}{8} = \frac{5}{14}\]
8/3 divided by (1/4 + 9/16) =
tell me what you get
i dont know how to divide
first add 1/4 + 9/16
what do you get here?
remember the denominators must be the same
10/20
no, the denominators must be the same before you add
then i dont get it
1/4 = x/16 what must be x?
4
so 1/4 = 4/16
1/4 + 9/16 turns into 4/16 + 9/16
when you add fractions, you do NOT add the denominators (only the numerators)
oh ok
the denominator will remain 16
ok
what do you get
13/16
so \[\large \frac{8}{3} \div \left(\frac{1}{4} + \frac{9}{16}\right)\] turns into \[\large \frac{8}{3} \div \frac{13}{16}\]
now you flip the second fraction and multiply \[\large \frac{8}{3} \div \frac{13}{16}\] \[\large \frac{8}{3} \times \frac{16}{13}\]
128/39
very good \[\large \frac{8}{3} \div \left(\frac{1}{4} + \frac{9}{16}\right)\] \[\large \frac{8}{3} \div \frac{13}{16}\] \[\large \frac{8}{3} \times \frac{16}{13}\] \[\large \frac{8*16}{3*13}\] \[\large \frac{128}{39}\]
dont we divide now
you can leave it as an improper fraction or you can convert that to a mixed number either way works
ok thank you
you're welcome
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