How many atoms are there in 95.3 g of barium chloride (BaCl2)?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abb0t):
multiply the given mass by the molar mass. then, proceed to multiply with avogadro's number: \(\sf \color{red}{6.022 \times 10^{23} \frac{atoms}{mol}}\)
OpenStudy (abb0t):
Molar mass = mass of barium \(\times\) \(\sf \color{Red}{2}\)(mass of chlorine)
the masses can be found on periodic table under the element.
OpenStudy (abb0t):
You can find their masses on here:
http://ptable.com/
just click on any element that you need and the mass comes up.
OpenStudy (anonymous):
so it would be 7.9X10^27
OpenStudy (anonymous):
it was incorrect
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abb0t):
You're close, but I think your power is wrong.
OpenStudy (abb0t):
It should not be 10\(^{27}\)
OpenStudy (anonymous):
i keep getting 27;O
OpenStudy (abb0t):
Try 10\(^{21}\)
OpenStudy (anonymous):
still incorrect:(
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yeah its not right still but thank you for your help!
OpenStudy (abb0t):
2.75 \(\times\) 10\(^{23}\)
OpenStudy (abb0t):
Sorry, I am using an old non-scientific calculator, I think that should be right now that I'm using my phone.