How many atoms are there in 95.3 g of barium chloride (BaCl2)?
multiply the given mass by the molar mass. then, proceed to multiply with avogadro's number: \(\sf \color{red}{6.022 \times 10^{23} \frac{atoms}{mol}}\)
Molar mass = mass of barium \(\times\) \(\sf \color{Red}{2}\)(mass of chlorine) the masses can be found on periodic table under the element.
You can find their masses on here: http://ptable.com/ just click on any element that you need and the mass comes up.
so it would be 7.9X10^27
it was incorrect
You're close, but I think your power is wrong.
It should not be 10\(^{27}\)
i keep getting 27;O
Try 10\(^{21}\)
still incorrect:(
yeah its not right still but thank you for your help!
2.75 \(\times\) 10\(^{23}\)
Sorry, I am using an old non-scientific calculator, I think that should be right now that I'm using my phone.
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