Find all values of theta where 0 degrees < 0 < 360 degrees.
a. csc(theta) = - √2
b. sin(theta) = -√3/2
c. sec(theta) = -1
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jimthompson5910 (jim_thompson5910):
how far did you get?
OpenStudy (anonymous):
Nothing.. Completely lost and I need to finish this asap.
jimthompson5910 (jim_thompson5910):
csc(theta) = 1/sin(theta)
jimthompson5910 (jim_thompson5910):
csc(theta) = - √2
1/sin(theta) = - √2
sin(theta) = - 1/√2
sin(theta) = -(√2 )/2
now use the unit circle to determine theta
jimthompson5910 (jim_thompson5910):
I'll let you take over. Tell me what you get
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OpenStudy (anonymous):
Um.. 4pi/3?
jimthompson5910 (jim_thompson5910):
close but no
OpenStudy (anonymous):
But -1/2 , -√2, 2 isn't stated on the unit circle. I'm unsure how to find the measurement.
jimthompson5910 (jim_thompson5910):
try looking for \(\large -\frac{\sqrt{2}}{2}\)
OpenStudy (anonymous):
That's in quadrants 3 & 4.
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jimthompson5910 (jim_thompson5910):
yes because sine is negative here
jimthompson5910 (jim_thompson5910):
which angles correspond to a point with a y coordinate of \(\large -\frac{\sqrt{2}}{2}\)
OpenStudy (anonymous):
225 , 315
jimthompson5910 (jim_thompson5910):
very good, you got them both
jimthompson5910 (jim_thompson5910):
so that is the solution to part A
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OpenStudy (anonymous):
Oh okay that makes much more sense!
jimthompson5910 (jim_thompson5910):
you are doing the same for each part
note: sec(theta) = 1/cos(theta)
jimthompson5910 (jim_thompson5910):
that's great
OpenStudy (anonymous):
Can you set the problems up again? Still confusing in that area.
jimthompson5910 (jim_thompson5910):
which one
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OpenStudy (anonymous):
B
jimthompson5910 (jim_thompson5910):
in part B you need to look at the unit circle for points that have y coordinates of \(\large -\frac{\sqrt{3}}{2}\)
jimthompson5910 (jim_thompson5910):
then report the angles (in degrees) for those corresponding points
jimthompson5910 (jim_thompson5910):
remember, sine deals with the y coordinate on the unit circle
OpenStudy (anonymous):
240 , 300?
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jimthompson5910 (jim_thompson5910):
both are perfect
OpenStudy (anonymous):
Awesome, what about C?
jimthompson5910 (jim_thompson5910):
sec(theta) = -1
1/cos(theta) = -1
cos(theta) = -1
now use the unit circle...BUT this time you're looking at the x coordinate (not y coordinate)
OpenStudy (anonymous):
180, ?
jimthompson5910 (jim_thompson5910):
and that's it, just 180
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OpenStudy (anonymous):
Awesome, thank you so much! Do you mind helping me out with coterminals?
jimthompson5910 (jim_thompson5910):
sure I can do a few more
OpenStudy (anonymous):
Find two angles, theta, coterminal with -25pi/8 where -2pi<theta<2pi.
jimthompson5910 (jim_thompson5910):
use a calculator to evaluate -25pi/8
what do you get
OpenStudy (anonymous):
-9.817
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jimthompson5910 (jim_thompson5910):
notice how -2pi = -6.28 roughly
jimthompson5910 (jim_thompson5910):
and 2pi = 6.28 roughly
jimthompson5910 (jim_thompson5910):
so clearly -25pi/8 is not in the interval -2pi<theta<2pi
OpenStudy (anonymous):
Okay
jimthompson5910 (jim_thompson5910):
to find any coterminal angles to a given angle (in radians) we just add/subtract 2pi
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jimthompson5910 (jim_thompson5910):
in this case, we add 2pi
jimthompson5910 (jim_thompson5910):
-25pi/8 + 2pi = ??
OpenStudy (anonymous):
Um.. -23pi/8?
jimthompson5910 (jim_thompson5910):
no, 2pi = 4pi/2
OpenStudy (anonymous):
Oh one sec
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jimthompson5910 (jim_thompson5910):
sorry I meant to say 2pi = 16pi/8
jimthompson5910 (jim_thompson5910):
-25pi/8 + 2pi
-25pi/8 + 16pi/8 = ??
OpenStudy (anonymous):
-9pi/8?
jimthompson5910 (jim_thompson5910):
now evaluate that with a calculator
OpenStudy (anonymous):
-3.53
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jimthompson5910 (jim_thompson5910):
is that in the interval
-6.28 < theta < 6.28
??
OpenStudy (anonymous):
Yes it is :)
OpenStudy (anonymous):
What about the other one?
jimthompson5910 (jim_thompson5910):
so that's one coterminal angle that's in the right interval we want
add 2pi to -9pi/8 to get the next coterminal angle
OpenStudy (anonymous):
7pi/8?
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jimthompson5910 (jim_thompson5910):
very good, you got the hang of this
OpenStudy (anonymous):
2.74
jimthompson5910 (jim_thompson5910):
so that's definitely in range too
jimthompson5910 (jim_thompson5910):
the two coterminal angles are
-9pi/8, 7pi/8
OpenStudy (anonymous):
Great thanks! I have 2 more different problems to solve rather quickly because I can figure the rest off the bases of these. Do you mind? You're a great help.
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jimthompson5910 (jim_thompson5910):
sure go for it
OpenStudy (anonymous):
Find the measure of the reference angle:
a. theta = 18pi/7
Find the radian measure of the angle:
theta = -270
degree measure of :
theta=8pi/12
Sorry 3 actually.
jimthompson5910 (jim_thompson5910):
evaluate 18pi/7 with a calculator
OpenStudy (anonymous):
8.07
jimthompson5910 (jim_thompson5910):
so that's definitely out of range of 0 < theta < 2pi
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jimthompson5910 (jim_thompson5910):
so we need to find the coterminal angle
subtract 2pi from 18pi/7 to get
18pi/7 - 2pi = ???
OpenStudy (anonymous):
Hmm the denominators are different..
jimthompson5910 (jim_thompson5910):
2pi = 14pi/7
jimthompson5910 (jim_thompson5910):
multiply top and bottom by 7
OpenStudy (anonymous):
Oh okay. So 4pi/7.
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jimthompson5910 (jim_thompson5910):
4pi/7 = 1.795
so 4pi/7 is definitely in the interval 0 < theta < 2pi
OpenStudy (anonymous):
Oh wait. This is to find the reference angle.
jimthompson5910 (jim_thompson5910):
the question is: which quadrant is 4pi/7 in?
well we could do a bunch of computations of pi/2, pi, 3pi/2 and compare, or we can convert 4pi/7 to degrees
jimthompson5910 (jim_thompson5910):
I would convert it over to degrees
so you multiply this by 180/pi to get
(4pi/7)*(180/pi) = (4pi*180)/(7*pi) = 720/7 = 102.857
now what quadrant is the angle 102.857 degrees in?
OpenStudy (anonymous):
2?
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jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
so we use this rule
Reference Angle = pi - (Given Angle)