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if f(t)= square root of 4/ t^5 find f'(t) and f'(3)
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f'=(-20t^4/t^10)/(2(sqrt(4/t^5) plug 3 into that for f'3
i don't get it
kidding
f' is the derivative of f(t)
you're an idiot too lol and i don't get why are you dividing everything in the numerator and powers
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There's a rule for square root derivatives. it's du/2sqrt(u)
thank you
thank you for being awesome
oh btw your answer is wrong
i didn't simply it
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it's just the form without any simplification so it's going to be wrong
ok do you know how to simplify it ?
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