graph y=IxI
|dw:1380171169971:dw|
oh man that is so vague, the cross repesents the x and y axes and the diagonal lines is the graph of y=|x|
can you maybe explain how you do this I have an exam over it tomorrow and my professor isn't the greatest
like these equations in general
sure, the |x| function just takes any negative values you may get, and makes them positive instead so for example say we had just regular y = x, when = -2, y = -2 but if it was y = |x| instead, when x = -2, y = 2 (just make it positive)
what do you need to know about it? just how to graph them?
i made a typo in my first post, i meant when x = -2, y = -2 in the third line
okay pretty much graph them one way then mirror it?
yes pretty much, graph them, and then any values which are negative (ie fall below the x axis, just make them positive instead
okay I have 1 more question lol sorry im horrible at math
its says solve the system by graphing. check the coordinates of the intersection point in both equations 3x+5y= -11 and 3x+5y=5
its fine. that question is tough to answer online here, because you would need an accurate graph how good are you at graphing regular equations? those 2 equations, when you rearrange them you'd get: \[y = -\frac{ 3 }{ 5 }x - \frac{ 11 }{5 }\] and \[y = -\frac{ 3 }{ 5 }x - 1\] and you would graph them, and then just look on your graph page at the point where they intersect, and read off the coordinated of that point, and that would be your answer.
whoa can you see my equation? I can't
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