Setting this up correctly? @ganeshie8 :) http://gyazo.com/98dd4189d312dc595af6acd469489125
I just don't know this? It's not like there is a theorem stating all chords are equal.
careful, intersecting chords theorem says this :- \(\text{product of segments of one chord, equals product of segments of second chord}\)
you just need to multiply, instead of adding.
according to intersecting chords theorem :- PA x PD = PC x PB
Ooh intersecting chords? Didn't know about that theorem..:)
:) hre is a simple visual explanation http://www.mathopenref.com/chordsintersecting.html
Question, there was a dispute about the answer to this: http://gyazo.com/cc8dc8d2f769560c334863c5ca4710ff
you've picked the correct option ! wat dispute ?
It was on a post of mine, people were just disagreeing haha. And this one? I think it is either C or D. http://gyazo.com/90a485642e2c6338214d7d0cf49e6dc3
I said C, but someone that was helping me said D then got off, so I just took their word :-P
D is correct ! after proving triangles, OSD & OTB are congruent, we use CPCTC and conclude OS = OT
how did u pick C, there is not a single ASA triangle i see in that diagram...
What makes OSD & OTB congruent?
lets prove this :) here is the theorem we want to prove :- Prove that congruent chords in a circle are equidistant from center
Are the triangles similar by AAS? Also, another question. http://gyazo.com/2fa9726f000ff4f11afdf7eb3df2fb8b
1) CD = AB 1) Given 2) OD = OB 2) radii of same circle 3) DS = BT 3) perp from center bisects the chord 4) \(\triangle OSD \cong \triangle OTB \) 3) By LH congruence theorem 5) OS = OT 5) Corresponding parts of congruent triangles are congreunt
thats for previous question okay
the pic and ur question are not relating, you asked Are the triangle similar by AAS, but in the pic i see squares and oly 1 triangle ??? check once :)
I was referring to the other question :P But I see how you get it now.
ohk i get u :)
pic shows a classic proof of Pythagorean theorem
It's D, right?
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