Question

7(x-8)=3(x+4)

Answer 1

Do you know of the distributive property?

Answer 2

yes 7x-56=3x+12

Answer 3

Solve for x:
\[7 x-56 = 3 x+12\]
Factor the polynomial, 7 x-56.
Factor 7 from the polynomial 7 x-56:
\[7 (x-8) = 3 x+12\]
Factor the polynomial, 3 x+12.
Factor 3 from the polynomial 3 x+12:
\[7 (x-8) = 3 (x+4)\]
Move everything to the left hand side.
Subtract 3 (x+4) from both sides of 7 (x-8) = 3 (x+4):
\[7 (x-8)-3 (x+4) = 3 (x+4)-3 (x+4)\]
Look for two terms that sum to zero.
\[3 (x+4)-3 (x+4) = 0:\]
\[7 (x-8)-3 (x+4) = 0\]
Distribute 7 over x-8.
\[7 (x-8) = 7 x-56:\]
\[7 x-56-3 (x+4) = 0\]
Distribute -3 over x+4.
\[-3 (x+4) = -12-3 x:\]
\[7 x+-12-3 x-56 = 0\]
Group like terms in 7 x-3 x-56-12.
Grouping like terms, 7 x-3 x-56-12 = (7 x-3 x)+(-56-12):
\[(7 x-3 x)+(-56-12) = 0\]
Combine like terms in 7 x-3 x.
\[7 x-3 x = 4 x:\]
\[4 x+(-56-12) = 0\]
Evaluate -56-12.
\[-56-12 = -68:\]
\[4 x+-68 = 0\]
Factor the polynomial, 4 x-68.
Factor 4 from the polynomial 4 x-68:
\[4 (x-17) = 0\]
Divide both sides by a constant to simplify the equation.
Divide both sides of 4 (x-17) = 0 by 4:
\[(4 (x-17))/4 = 0/4\]
Any nonzero number divided by itself is one.
\[4/4 = 1:\]
\[x-17 = 0/4\]
Any number times zero is zero.
\[0/4 = 0:\]
\[x-17 = 0\]
Isolate terms with x to the left hand side.
Add 17 to both sides:
\[x+(17-17) = 17\]
Look for two terms that sum to zero.
\[17-17 = 0:\]
Answer:
\[x = 17\]

Answer 4

Problem analysis:
\[7x-56=3x+12\]
Combine like terms:
\[7x+3x=56+12\]
\[10x=68\]
\[x=6.8\]

Answer 5

x=17

Answer 6

when we move a number from 1 side of = then their sign will change