√8 + 6/√2
8=?
the question says that i have to simplify fully
\[\sqrt{8} + \frac{ 6 }{ \sqrt{2}}\]
Well, how do you add fractions?
\[\sqrt8 + \frac{6}{\sqrt2} =\sqrt{2^2 \times 2} + \frac{3 \times 2}{\sqrt2}\] \[=2\sqrt{ 2} + \frac{3 \times \sqrt 2 \times \sqrt2}{\sqrt2} =2\sqrt{ 2} + 3\sqrt2 = 5\sqrt2\]
Always keep any eye out for multiple avenues. \(\sqrt{8} + \dfrac{6}{\sqrt{2}} = \sqrt{8}\dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{\sqrt{16} + 6}{\sqrt{2}} = \dfrac{4+6}{\sqrt{2}} = \dfrac{10}{\sqrt{2}} = \dfrac{10\sqrt{2}}{2} = 5\sqrt{2}\) Don't get caught in one way of thinking. Sometimes one way is easier or better and sometimes another.
* Whoops! Missing the \(6/\sqrt{2}\) in that second piece.
i'm so confused about this I just understand that square root of 8 simplifies to 2 \[\sqrt{2}\]
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