What is the slope of a line that passes through the point (−2, 3) and is parallel to a line that passes through (3, 7) and (−2, −8)?
@agent0smith
FIrst: Use (3, 7) and (−2, −8) to find the slope, m = (y2-y1)/(x2-x1)
Parallel lines have the same slope. Then, use point-slope form, y-y1 = m(x-x1) to find the equation of the line.
wait please say that in a different way
so I use the formula y = mx + b over here?
No... use (3, 7) and (−2, −8) to find the slope,\[\Large m = \frac{ y_2 - y_1 }{ x_2 - x_1 }\] That's the slope of the line, since parallel lines have the same slope. THEN once you have m, \[\Large y-y_1 = m(x-x_1)\] using the point (−2, 3) as (x1, y1)
-15/-5? which is also 3
Good, that's m. Now work on the second part.
I don't know how
@agent0smith
Follow the steps, they're in my last post.
ok
but which one will be y?
See the above post... you have m, and x1 and y1, now plug them into that equation. y will be y and x will be x.
oh
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