Question

dy/dx = e^x^2
find coordinates of any turning points??

Answer 1

Turning points would mean that the graph of the function goes from increasing to decreasing or vice-versa, which means that there would be a local min or max, which means that the 1st derivative would = 0.

so..... for what value of x would \(\large e^{x^2}=0\)?

Answer 2

and then how do I get the point(s)?

Answer 3

Well, if/when you find values of x that solve that equation, you would need the anti-derivative.

But don't worry about that just yet. What do you think about the solutions to the equation, \(\large e^{x^2}=0\)? Hmmmm?

Answer 4

That equation doesn't seem to have real solutions.

Answer 5

That's correct. :) Because x^2 is always positive, and when you take a positive number (e) to a postive power, you won't ever get 0.

Answer 6

the answer is supposed to be 18

Answer 7

How so? That isn't coordinates of a point. Are you sure that you're reading the problem correctly?

Answer 8

I mean, you said "find coordinates of any turning points".... so how is "18" the coordinates of a turning point?

Answer 9

@yaysocks