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OpenStudy (anonymous):
Use L'Hospitals Rule Limx->1 lnxtan(pi x/2)
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OpenStudy (anonymous):
\[\lim_{x \rightarrow 1}lnx \tan Pix/2)\]
OpenStudy (anonymous):
\[\lim_{x \rightarrow 1}lnx *\tan(\pi x/2)\] \[\lim_{x \rightarrow 1} \frac{ lnx }{ \cot(\frac{ \pi x }{2 } )}\]
OpenStudy (anonymous):
I thought the d/dx of tan is sec^2x, no?
OpenStudy (anonymous):
oooh oh oh, i see
OpenStudy (anonymous):
I set it up wrong, its 1/tan. im not ready to take d/dx
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OpenStudy (anonymous):
i put in this form (0/0)
OpenStudy (anonymous):
me jumping ahead of myself
OpenStudy (anonymous):
you can now use L'Hospitals Rule.
OpenStudy (anonymous):
right, ASAAD123 you are the best. thank you for all your help!!!
OpenStudy (anonymous):
welcome ^__-__^ ---
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