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Mathematics 8 Online
OpenStudy (anonymous):

g(x)=-log(x)+2

jimthompson5910 (jim_thompson5910):

What do you want to do here?

OpenStudy (isaiah.feynman):

I get a little irritated when people just write an expression without saying what they want to be done to that expression and leave.

OpenStudy (anonymous):

Description of transformation: Equation(s) for the Vertical Asymptote(s): x-intercept in (x, y) form Im sorry please help me this is what i need

OpenStudy (isaiah.feynman):

So you want to find the x intercept??

OpenStudy (anonymous):

this is what my teacher gave me and then she gave me another problem but this what she wrote on the top to do the problems Describe the transformations on the following graph of f (x)  log( x). State the placement of the vertical asymptote and x-intercept after the transformation. For example, vertical shift up 2 or reflected about the x-axis are descriptions

jimthompson5910 (jim_thompson5910):

since you cannot take the log of 0 or any negative number, this means that the vertical asymptote is x = 0 this is the vertical boundary that the graph approaches, but never gets to it

jimthompson5910 (jim_thompson5910):

to find the x-intercept of y = -log(x) + 2 plug in y = 0 to get 0 = -log(x) + 2 now solve for x

OpenStudy (anonymous):

this was the question g(x)=-log(x)+2 Description of transformation: Equation(s) for the Vertical Asymptote(s): x-intercept in (x, y) form:

jimthompson5910 (jim_thompson5910):

if you start with y = log(x) and change it to y = -log(x), then you have reflected the original over the x axis to get the new graph if you add 9 to the end, you are shifting the second graph up 9 units so that explains how the graphs are related

OpenStudy (anonymous):

im still lost sorry

jimthompson5910 (jim_thompson5910):

where are you lost

OpenStudy (isaiah.feynman):

|dw:1380236774129:dw| To illustrate what jim thomspon is saying.

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