A car, moving along a straight stretch of high-
way, begins to accelerate at 0.0421 m/s2. It
takes the car 35.2 s to cover 1 km.
How fast was the car going when it first
began to accelerate?
Answer in units of m/s

Question

A car, moving along a straight stretch of high-
way, begins to accelerate at 0.0421 m/s2. It
takes the car 35.2 s to cover 1 km.
How fast was the car going when it first
began to accelerate?
Answer in units of m/s

agent0smith · Answer

If you're familiar with this  $$\Large d = vt + \frac{ 1 }{ 2} a t^2$$
you can use it to find v (the initial speed)

d distance, in m, so convert 1km to m.

t is time in seconds

a is accel. in m/s^2

anonymous · Answer

I got 27.6681 as v

agent0smith · Answer

Looks reasonable for the context of a question, a car on a highway.

anonymous · Answer

Yep that's what I got.

agent0smith · Answer

To go from m/s  to km/h, multiply by 3.6

So 27.6 m/s, times 3.6, gives about 100km/h... reasonable highway speed

agent0smith · Answer

To go from km/h to m/s, divide by 3.6

100 km/hr divided by 3.6 is about 27.6 m/s

anonymous · Answer

thanks :)