A football is thrown at an angle of 50◦ above
the horizontal. Assume the ball is throw and
received at the same height.
To throw a 59.6 m pass, what must be the
initial speed of the ball? The acceleration due
to gravity is 9.8 m/s2 .
Answer in units of m/s

Question

A football is thrown at an angle of 50◦ above
the horizontal. Assume the ball is throw and
received at the same height.
To throw a 59.6 m pass, what must be the
initial speed of the ball? The acceleration due
to gravity is 9.8 m/s2 .
Answer in units of m/s

agent0smith · Answer

Hopefully you've seen the range equation $$\Large R = \frac{ v_o ^2 \sin 2 \theta }{ g }$$ 
R is distance, theta is angle, v0 is initial velocity

note this equation ONLY APPLIES FOR NO CHANGE IN HEIGHT

anonymous · Answer

sin2(50) does that equal to sin(100) I've always wondered that

agent0smith · Answer

Yes. It's sin(2 theta) not sin2 * theta, since that wouldn't make much sense anyway

anonymous · Answer

Oh well I got 24.3524 m/s

agent0smith · Answer

Well then, good job :)

anonymous · Answer

Thank you :)