Calculate the equivalent capacitance of the circuit shown in the diagram above, where C1=8.05 μF, C2=6.65 μF, C3=8.30 μF, and C4=2.50 μF.

Question

anonymous · Answer

attachment

plainntall · Answer

It looks like C3 and C4 are in series and they are in parallel with C1 and C2 which are also in parallel with each other.

plainntall · Answer

So that means Ceq= C1 + C2 +(1/((1/C3)+(1/C4))

anonymous · Answer

excellent.... Its correct.. do you mind explaining why?

plainntall · Answer

The formula for equivalent capacitance in paralell is C1+C2+... all the other capacitors that are in parallel.

The formula for invers of the equivalent capacitance for series is (1/c1 ) + (1/c2) _...all the other capacitors in series.

plainntall · Answer

For the derivation of the formulas I would recommend reading your book or checking out http://farside.ph.utexas.edu/teaching/302l/lectures/node46.html

anonymous · Answer

this was clear enough than how my prof explained.. Thank you very much