Find the sum of the series when it converges. (if geometric, find the first term, the ratio and the sum)
\[\sum_{\infty}^{n=0}2(\frac{ 2 }{ 3 })^{n}\]
Ok, so you do know the formula for the sum of an infinite geometric series, it's actually one easy one to remember once you know it.
What is the 1st term?
im not sure the formula.
well do you mean the lim n->inf r^n = 1 if r<1 and 0 if |r|<1
$$ \Large{ \sum_{n=0}^\infty 2\left ( \cfrac{2}{3}\right )^n\\ =2\times\left ( \cfrac{2}{3}\right )^0+2\times\left ( \cfrac{2}{3}\right )^1+\cdots\\ =2\times1+2\times\left ( \cfrac{2}{3}\right )+\cdots\\ =2+\cfrac{4}{3}+\cdots\\ } $$ Make sense so far?
Do you see the 1st term?
The terms in parenthesis above is the ratio
The formula for the sum uses this ratio: $$ \sum_{n=0}^\infty 2\left ( \cfrac{2}{3}\right )^n\\ =2\left ( \cfrac{1}{1-a}\right )\\ $$ Where \(a\) is the ratio you found above.
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