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Trigonometry
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How do you solve the inequality 4-Ix+3I<2 its the absolute value of x+3
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first solve for \(|x+3|\)
subtract \(4\) and get \[-|x+3|<-2\] then change the signs and the inequality to get \[|x+3|>2\] and solve that one by solving two inequalities \[x+3<-2\] or \[x+3>2\]
i got a final answer of x>-1 and x<-5 is that correct
yes
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