Consider the function f(x)=(8-x)/(x+9)+2 Algebraically determine the domain and all of the intercepts.
\[x + 9 \ne 0\]\[f(x) \ne -1\]
To find the intercepts, set f(x) = 0, then solve for x. Then set x = 0, then solve for f(x)
How did you get f(x)=-1?
Just by looking at the function really. I know that x + 9 is in the denominator, but when you are solving for x you usually multiply both sides by x + 9 to get rid of the denominator. But if both sides of the equation have -x, then there is no solution. The only way to get -x on both sides is if f(x) = -1
Actually, I didn't see the + 2
That changes things
Alrighty, well I go a different answer. When I solved for x I got -26 and for the domain I got x can't equal -9 so the domain would be [(-\infty,-9)(-9,\infty)\]
opps \[(-\infty,-9)(-9,\infty)\]
You found what x cannot equal, not what f(x) cannot equal.
I agree that \(x \ne -9\)
I don't think you have to worry about what \(f(x)\) cannot equal since it doesn't ask you to find the range.
Your domain appears to be correct. Now if you manage to find the intercepts, then you'll be all set.
Because of the + 2, \(f(x) \ne 1\). You would only need to know that if you were trying to find the range.
Mmkay! Thanks. Now, I just gotta find the intercepts!
I already posted what to do to find the intercepts.
I know I'm solving it haha.
Okay, good luck.
I got x-intercept (-26,0) Y- intercept (0, 26/9)
That appears to be correct.
Thanks for the help.
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