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Chemistry 10 Online
OpenStudy (anonymous):

someone help me please!!!

OpenStudy (anonymous):

OpenStudy (aaronq):

notice the starting concentrations are doubling, but the rate is not doubling, it's increasing faster. if you divide the rates \(\dfrac{rate_2}{rate_1}\) and \(\dfrac{rate_3}{rate_2}\)=8 you notice that it's increasing to the power of 8, which is cubic. so the rate law is: \( rate=k[A]^3\)

OpenStudy (aaronq):

i meant "increasing by 8" not "to the power of 8"

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