Question

To solve this system using the addition method, you would need to multiply the first equation by what number in order for the x's to add out?

2x + 3y = 8
-6x + 4y = 11

Answer 1

Thats simultaneous right

Answer 2

addition methods

Answer 3

might be what u said

Answer 4

i got the answer lol

Answer 5

X=-1/26
Y=35/13

Answer 6

3
-3
6
are my option

Answer 7

we want to multiply the first equation by a number so that when we add the two equations the x's cancel out
so we want the x in the first equation to be 6x
what do we multiply 2x by to make it 6x?

Answer 8

3?

Answer 9

correct

Answer 10

we want it to be 6x so that when we add the first equation to the second the x's "go away"
6x+(-6x)=0

Answer 11

yayyy what about 3x - y = 3
-2x + 2y = 6

Answer 12

well we have -2x on the bottom so we want 2x on the top
what do we multiply 3x by to get 2x?

Answer 13

\[3x*\frac{?}{?}=2x\]

Answer 14

answer be 2?

Answer 15

2*3x = 2x?

Answer 16

noo 6x ?

Answer 17

\[3x*\frac{2}{3}=\cancel{3}x*\frac{2}{\cancel{3}}=2x\]

Answer 18

so the answer would be 6?

Answer 19

no
I asked you what do we need to multiply 3x by to get 2x
you answerd 2
I showed you that 2*3x does not equal 3x it equals 6x

Answer 20

what did I multiply 3x by to get 2x ?

Answer 21

im not sure :(