Question

lim (1/(1-cosx))-(2/x^2)

Answer 1

your question does not have the limit for which you want the solution

Answer 2

x=0

Answer 3

x->0

Answer 4

yes

Answer 5

there is a difference i hope u understand that

Answer 6

its x approaches 0

Answer 7

first make them one fraction
then use l'hospital rule again and again..

Answer 8

(l'hospital rule 4 times i think)

Answer 9

is the answer infinity......

Answer 10

no

Answer 11

the answer is 1/6
but i am trying to get the steps

Answer 12

yes.. it is 1/6.
as i said make it one fraction first
then use l'hospital rule for like 4 times

Answer 13

i tried it and its does not work with me

Answer 14

\[\frac{ 1 }{ 1-cosx } - \frac{ 2 }{ x^2 }\]
Is this the question? I am getiing infinity and I am not using L'hospital's rule

Answer 15

\[\frac{ x^2(1+cosx) - 2 \sin^2x }{ x^2\sin^2x }\]

Answer 16

Dividing nr and dr by x^2

Answer 17

oh yeah i got it I am wrong :P

Answer 18

You have to apply L'Hopital rule 4 times, right. Do you know how?