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OpenStudy (anonymous):
anyone able to help me?
OpenStudy (anonymous):
ln(a) - ln(b) = ln(a/b)
OpenStudy (anonymous):
oh yeahh..but i still cant solve for \(C\) in that form
OpenStudy (anonymous):
or am i, on the wrong track
OpenStudy (anonymous):
mm..
so we have
ln of:
(b^2+1)^(0.5) / (3b+1)^(c/3)
now if the power of b in the numerator will be bigger or smaller than the power of b in the denominator the integral will diverge since
ln of something goes to 0 goes to - inf
and ln of something goes to inf goes to inf.
so the powers should be equal
then ill go with
c/3 = 1
c = 3.
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OpenStudy (anonymous):
so do i just guess the number 1?
OpenStudy (anonymous):
1 ?
i just wrote c=3
OpenStudy (anonymous):
no guessing ..
in the numerator you have ~ (b^2)^0.5 = b = b^1
denominator ~ (b)^(c/3)
c/3 = 1
OpenStudy (anonymous):
isnt it (3b)^(c/3)?
OpenStudy (anonymous):
yes but it does not matter for the value of c
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OpenStudy (anonymous):
can i just multiply it like (b^2)^(0.5? is that allowed, cos normally you expand it, not time the inside..
OpenStudy (anonymous):
since b-> inf the 1 inside is negligible
OpenStudy (anonymous):
ohhh
OpenStudy (anonymous):
i got it now
OpenStudy (anonymous):
we only need to find the value of c so that the integral converge
so you dont really need to find exactly how the expression looks like
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