integral
anyone able to help me?
ln(a) - ln(b) = ln(a/b)
oh yeahh..but i still cant solve for \(C\) in that form
or am i, on the wrong track
mm.. so we have ln of: (b^2+1)^(0.5) / (3b+1)^(c/3) now if the power of b in the numerator will be bigger or smaller than the power of b in the denominator the integral will diverge since ln of something goes to 0 goes to - inf and ln of something goes to inf goes to inf. so the powers should be equal then ill go with c/3 = 1 c = 3.
so do i just guess the number 1?
1 ? i just wrote c=3
no guessing .. in the numerator you have ~ (b^2)^0.5 = b = b^1 denominator ~ (b)^(c/3) c/3 = 1
isnt it (3b)^(c/3)?
yes but it does not matter for the value of c
can i just multiply it like (b^2)^(0.5? is that allowed, cos normally you expand it, not time the inside..
since b-> inf the 1 inside is negligible
ohhh
i got it now
we only need to find the value of c so that the integral converge so you dont really need to find exactly how the expression looks like
yee, got it thankk youuuu!! :D
yw :)
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