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Mathematics 16 Online
OpenStudy (anonymous):

integral

OpenStudy (anonymous):

anyone able to help me?

OpenStudy (anonymous):

ln(a) - ln(b) = ln(a/b)

OpenStudy (anonymous):

oh yeahh..but i still cant solve for \(C\) in that form

OpenStudy (anonymous):

or am i, on the wrong track

OpenStudy (anonymous):

mm.. so we have ln of: (b^2+1)^(0.5) / (3b+1)^(c/3) now if the power of b in the numerator will be bigger or smaller than the power of b in the denominator the integral will diverge since ln of something goes to 0 goes to - inf and ln of something goes to inf goes to inf. so the powers should be equal then ill go with c/3 = 1 c = 3.

OpenStudy (anonymous):

so do i just guess the number 1?

OpenStudy (anonymous):

1 ? i just wrote c=3

OpenStudy (anonymous):

no guessing .. in the numerator you have ~ (b^2)^0.5 = b = b^1 denominator ~ (b)^(c/3) c/3 = 1

OpenStudy (anonymous):

isnt it (3b)^(c/3)?

OpenStudy (anonymous):

yes but it does not matter for the value of c

OpenStudy (anonymous):

can i just multiply it like (b^2)^(0.5? is that allowed, cos normally you expand it, not time the inside..

OpenStudy (anonymous):

since b-> inf the 1 inside is negligible

OpenStudy (anonymous):

ohhh

OpenStudy (anonymous):

i got it now

OpenStudy (anonymous):

we only need to find the value of c so that the integral converge so you dont really need to find exactly how the expression looks like

OpenStudy (anonymous):

yee, got it thankk youuuu!! :D

OpenStudy (anonymous):

yw :)

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