can anyone help me with this proof.
\[a^2+b^2+c^2-(2ab+2bc+2ca)\ge \frac{ 4 }{ \sqrt{F} }\]
where a,b,c are the sides of a triangle and F is the area.
Someone please give a hint,
I'm wondering if it has something to do with Heron's formula? http://www.mathsisfun.com/geometry/herons-formula.html Sorry, I'd try to work with you on it, but I'm short on time right now.
Maybe @amistre64 has an idea....?
proof, by induction?
induction ?
you cant possibly test each and every triangle can you?
the left side is almost: (a-b-c)^2
I am not getting anything could you please help me more in this matter.
\[a^2+b^2+c^2-(2ab+2bc+2ca)\ge \frac{ 4 }{ \sqrt{F} }\] \[(a-b-c)^2-4bc\ge \frac{ 4 }{ \sqrt{F} }\]
I have to prove the equation it is not provided, i have to prove with the help of the given information,
May be I require a diagram and then proceed with prerequisite.
diagrams are always nice when they can be drawn
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