I need help putting up the equation A brother and sister have weight (pounds) that varies as the cube of height (feet) and they share the same proportionality constant. The sister is 6 feet tall and weighs 170 pounds. Her brother is 6'4" tall. How much does he wait?
weight varies as the cube of height so basically weight = height^3
and a proportionality constant :)
yes, what about the term , proportionality constant ?
weight = constant * height^3
Make units to how much an inch weights. Then compare those units to the boy.
@HyperChemist 12 Inch = 1 foot ?
Yes
Sorry phanta, you must of misunderstood something, which is weird because it's really clear. Divide the height of the person to the weight. Hence to make 1 inch equal whatever weight you get. Then, multiply how much one inch in height weights to the height of the boy.
ok,so the sister is 6 x 12 = 60+12 = 72 Inches and the brother is 6 ft + 4 inch = 72 + 4 = 76 inches
That is indeed one way to solve the problem , but I'm looking for the solution where we use the equation , weight = k ( height)^3 then getting the weight of the boy.
wait I'll re-write with k instand of "constant"
@phanta_seea , what is the equation for the boy's weight ?
:)
we want to get the constant k to determine the boy's weight: weight = k * height^3 weight / k = height^3 k/ weight = 1/ height^3 <- reciprocal of the above k = weight/height^3
@yamyam70 the equation for the boy's weight is just this: weight = k ( height)^3 however we need to know the proportionality constant to be able to gete the weight
weight =the value of k from girl times (6'4")^3 ?
yes :)
@phanta_seea much thanks man :)
original equation: weight = k * height^3 solve for k, by dividing height on both sides k = weight/height^3 plug in girl values: k = 170 pounds /(72 Inch)^3 with 6 ft = 72 Inch
@phanta_seea thanks :))
no problem
something is wrong man
oh nevermind
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