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Mathematics 7 Online
OpenStudy (anonymous):

How would I find the inequality for this graph? Im stuck :/ Graph in comments::

OpenStudy (anonymous):

OpenStudy (anonymous):

it's probably an absolute bracket responsible for this

OpenStudy (anonymous):

when the value gets negative, the function rises again

OpenStudy (anonymous):

usually the lowest point would be in the origin they've offset the function by both x and y

OpenStudy (anonymous):

Oh? I'm horrible at math so what does it being offset mean?

OpenStudy (anonymous):

that the y-intercept is not 0 and the x- intercept is not 0 :)

OpenStudy (anonymous):

ah ok.

OpenStudy (anonymous):

the drawing is for: y> |x| |dw:1380295412609:dw|

OpenStudy (anonymous):

that's the type of equation they've derived it from

OpenStudy (anonymous):

Ok, now I see what they were wanting to get at, but how would I form the points into an inequality?

OpenStudy (anonymous):

by "moving" the line of the inequality y >= |x|

OpenStudy (anonymous):

they have moved it up one "y" and to the right "5x"

OpenStudy (anonymous):

so I would replace the x and y with the numbers?

OpenStudy (anonymous):

to move a function up, you place +b y=mx+b to get it 3 higher than the usual through origin, you do y=mx+3

OpenStudy (anonymous):

y >= |x| y >= |x| +1

OpenStudy (anonymous):

so if x=0, then y has to be greater than 1 :)

OpenStudy (anonymous):

that's for the y-intercept

OpenStudy (anonymous):

also to change the x-intercept they do something like move function 2 to the right: y = mx(-2) + b

OpenStudy (anonymous):

so it'd be 6>=5? or something like that?

OpenStudy (anonymous):

you need an equation because it's not in the origin

OpenStudy (anonymous):

with variables

OpenStudy (anonymous):

hmmm... which equation would I use for the numbers? Im sorry if I am coming off dumb, I just can't grasp math.

OpenStudy (anonymous):

I believe this equation would work: y >= |x-5| +1

OpenStudy (anonymous):

So I wouldn't add the 6 into the equation?

OpenStudy (anonymous):

the function would usually never cross y=6, that's only because we have the absolute brackets and the function is "mirrored"

OpenStudy (anonymous):

Oh ok.. I see what yur saying. Thank you for helping me with this :)

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