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Mathematics 19 Online
OpenStudy (anonymous):

Part 1: Using complete sentences, explain what the discriminant is and what it tells you about the solutions of a quadratic equation. (4 points) Part 2: Provide a unique example to back up your explanation. (4 points) Can someone please help me out? I just don't know how to explain this and it's my last question. (:

OpenStudy (yamyam70):

so basically we are trying why is b^2 -4ac important in finding the roots..

OpenStudy (yamyam70):

Good question though.

OpenStudy (anonymous):

That's it? It's important for finding roots?

OpenStudy (yamyam70):

no no, I only stated the formula for the discriminant , .. (b^2 -4ac)

OpenStudy (anonymous):

OH lol well, I'm just trying to figure out this part, "and what it tells you about the solutions of a quadratic equation."

OpenStudy (yamyam70):

one moment

OpenStudy (anonymous):

Okay (:

OpenStudy (yamyam70):

so the discriminant tells you if a trinomial is factorable or not . If and only if the resulting answer is a perfect square :)

OpenStudy (anonymous):

That makes sense, thanks! Can you also help me come up with an example?

OpenStudy (yamyam70):

Hmmm well I can give you an example but I can't give you a "unique" example. :D here are some guidelines.. try out some trinomial, or make your own trinomial. Then solve for the discriminant. you can tell the purpose of the discriminant by doing that :)

OpenStudy (yamyam70):

Show your solution and you have an example :)

OpenStudy (anonymous):

I'm sorry, but how is a trinomial set up? I am drawing a total blank...I swear I know it

OpenStudy (yamyam70):

by definition , a trinomial has three terms hence, \[ax^2 + b x + c\]

OpenStudy (anonymous):

okay thanks! I kept wanting to switch ax^2 and bx lol gimme a sec (:

OpenStudy (yamyam70):

:)

OpenStudy (yamyam70):

you can switch it if you want, but to avoid confusion we take the standard form :)

OpenStudy (anonymous):

Would this be a good one to work with? I kinda just threw numbers together 2x^2 + 4x + (10)(2)

OpenStudy (yamyam70):

or you can say, 2x^2 + 4x + 20 :))

OpenStudy (anonymous):

lol I yeah I could x]

OpenStudy (yamyam70):

give it a try :)

OpenStudy (anonymous):

Okay hold on (:

OpenStudy (yamyam70):

*holds on

OpenStudy (anonymous):

would it be 4x^2 - 4(4)(20) for the first step? I just want to make sure I am doing it right

OpenStudy (yamyam70):

The formula for the discriminant is b^2 - 4 a c where , a b and c are constants :)

OpenStudy (anonymous):

Yeah and I plugged them all in. That's how I go 4x^2 - 4(4x)(20)

OpenStudy (anonymous):

I'm confusing myself D:

OpenStudy (yamyam70):

what I mean about constants are, constants are numbers, variables are letters

OpenStudy (anonymous):

I know that, I'm just lost on what the steps are :l

OpenStudy (yamyam70):

substitution. \[ax^2 + bx + c \]

OpenStudy (yamyam70):

a, b and c are constants :)

OpenStudy (yamyam70):

you just substitute numbers :) don't plug in variables

OpenStudy (yamyam70):

and then follow the order of operations , PEMDAS

OpenStudy (anonymous):

okay, so my example was was 2x^2 + 4x + 20. The discriminant formula is b^2 - 4(a)(c) What I don't understand is in the formula, b is squared, but in my example, a is squared. How do I get rid of a^2?

OpenStudy (anonymous):

Does that make any sense?

OpenStudy (yamyam70):

b^2 is indeed the formula. what is b in your example ?

OpenStudy (anonymous):

4

OpenStudy (yamyam70):

correct then what is (4)^2 ?

OpenStudy (yamyam70):

what is the value of , (4)^2 - 4 (2) (20) ?

OpenStudy (anonymous):

16 - 160?

OpenStudy (yamyam70):

yep :)

OpenStudy (yamyam70):

then subtract see if it has a perfect square if not, its not factorable :)

OpenStudy (anonymous):

Would it be -144 or positive 144?

OpenStudy (yamyam70):

- 144

OpenStudy (yamyam70):

bigger number always wins the signs when adding and subtracting :)

OpenStudy (anonymous):

Just making sure lol so the I would have to multiply the sqrt of -1 times the sqrt of 144 which makes it \[i \sqrt{144}\] right?

OpenStudy (anonymous):

And then factor it out since it is a perfect square?

OpenStudy (yamyam70):

i like the way you think :) go on :)

OpenStudy (anonymous):

:D Okay, so then it would factor out to be sqrt 2 ?

OpenStudy (anonymous):

or would it be sqrt 12?

OpenStudy (yamyam70):

\[i \sqrt{144} = 12i\]

OpenStudy (anonymous):

Oops, forgot the i lol

OpenStudy (anonymous):

You deserve a medal my friend! :D

OpenStudy (yamyam70):

thanks haha :) hope you can take care of the rest :)

OpenStudy (anonymous):

Yep I can! Thank you so much! You helped out a bunch!

OpenStudy (yamyam70):

haha :D

OpenStudy (yamyam70):

don't forget to close the question :)

OpenStudy (anonymous):

Okay (:

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