Question

If g(x) = 3x + 1, evaluate g(-14).


a.-41
b.-10
c.-5

Answer 1

Plug in -14 for x. You will get the answer.

Answer 2

how about If f(x) = x 2 + 1 and g(x) = 3x + 1, find f(2) + g(3).


a.5/3
b.12
c.15

Answer 3

Did you get the answer for previous question?

Answer 4

yes -41

Answer 5

How?

Answer 6

f(x)= x^2 + 1
f(2)= (2)^2+1
f(2)=4+1
f(2)=5

g(x) = 3x + 1
g(3) =3(3)+1
g(3)=9+1
g(3)=10.

f(2) + g(3)
5+10
______________

Answer 7

f(x) = x 2 + 1 and g(x) = 3x + 1, find f(2) + g(3)

This is a 2 part question.

So f(2) = (2)^2 +1
and
g(3) = 3(3) + 1

so f(2) = 5 and g(3) = 10

Last question: find f(2) + g(3)

5 + 10 = 15

Answer 8

what about

If f(x) = x^2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] ^2.

a.1
b.2
c.9

Answer 9

Same process as last question. Plug in 2 for f(x), 1 for g(x)

f(2) = (2)^2 + 1 = 4 +1 = 5
g(1) = 3(1) + 1 = 3 +1 = 4

Plug in f(2) = 5 and g(1) = 4 to [f(2)-g(1)] ^2.

you get [5-4]^2, by using PEMDAS we get

[1]^1 = 1 * 1 = "1"