Question

Limits,

I have to find this limit: http://screencast.com/t/3pc0fpKoqY

That's the solution of the problem: http://screencast.com/t/qGzfeoIYx <--- where did he find that 3x ?

Answer 1

That 3x is just to find the derivative of it.

Answer 2

see here: http://screencast.com/t/wYvgD1LUaf 3x is had already the chain rule applied to it

Answer 3

I know other ways too, it just confuses me

Answer 4

this way*

Answer 5

Can you please help me with my question ? :P

Answer 6

differentiation of e^3x is e^3x*3x

Answer 7

then why it goes 9e^3x in the solution

Answer 8

which step u confused in?

Answer 9

red one?

Answer 10

http://screencast.com/t/sNkRIGAym

Answer 11

\[\Huge \frac {d}{dx}(e^{3x})=e^{3x} \times 3x \times \frac{dx}{dx}\]
agree?

Answer 12

chain rule

Answer 13

thanks

Answer 14

np if u got it ^^

Answer 15

but if that was the case then it would be: e^(3x)9x Would it ? :)

Answer 16

what's dx/dy of e^(5x) ? Please answer me this and I will understand all

Answer 17

http://www.wolframalpha.com/input/?i=d%2Fdx+e%5E%283x%29 @DLS

Answer 18

derivative of e^(3x) is 3e^(3x)

derivative of e^(5x) is 5e^(5x)

derivative of e^(x^2) is 2x*e^(x^2)

Answer 19

\[\huge \frac{ d }{ dx } e^{f(x) }= f'(x) e^{f(x)}\]