Question

The pH of a solution at 25°C in which [OH–] = 3.8 x 10–5 M is....

4.42
4.79
9.58
11.08

Answer 1

\(\sf \color{red}{pH = -log[H^+]}\) and \(\sf \color{blue}{pOH = -log[OH^-]}\)
similarly, \(\sf \color{orange}{[H^+] = 10^{-pH}}\) and \(\sf \color{purple}{[OH^-] = 10^{-pOH}}\)
and finally, \(\sf \color{green}{pH + pOH = 14 }\)